pub fn formatNumber(self: Const, w: *std.Io.Writer, number: std.fmt.Number) std.Io.Writer.Error!void 2442
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2457 pub fn formatNumber(self: Const, w: *std.Io.Writer, number: std.fmt.Number) std.Io.Writer.Error!void {
const available_len = 64;
if (self.limbs.len > available_len)
return w.writeAll("(BigInt)");
var limbs: [calcToStringLimbsBufferLen(available_len, 10)]Limb = undefined;
const biggest: Const = .{
.limbs = &@as([available_len]Limb, @splat(comptime math.maxInt(Limb))),
.positive = false,
};
var buf: [biggest.sizeInBaseUpperBound(2)]u8 = undefined;
const base: u8 = number.mode.base() orelse @panic("TODO print big int in scientific form");
const len = self.toString(&buf, base, number.case, &limbs);
return w.writeAll(buf[0..len]);
}
If the absolute value of integer is greater than or equal to
pow(2, 64 * @sizeOf(usize) * 8), this function will fail to print the string, printing "(BigInt)" instead of a number. This is because the rendering algorithm requires reversing a string, which requires O(N) memory. SeetoStringandtoStringAllocfor a way to print big integers without failure.