pub fn removeByPtr(self: *Self, key_ptr: *K) void
Delete the entry with key pointed to by key_ptr from the hash map. key_ptr is assumed to be a valid pointer to a key that is present in the hash map.
TODO: answer the question in these doc comments, does this increase the unused capacity by one?
self: *Self
key_ptr: *K
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pub fn removeByPtr(self: *Self, key_ptr: *K) void { self.unmanaged.removeByPtr(key_ptr); }
Delete the entry with key pointed to by key_ptr from the hash map. key_ptr is assumed to be a valid pointer to a key that is present in the hash map.
TODO: answer the question in these doc comments, does this increase the unused capacity by one?